Formula: τ = R × C
Represents the time for a capacitor to charge to ~63.2% of supply voltage.
Circuit Diagram
Practice Problems
Problem 1
Given R = 10 kΩ and C = 100 μF, find the time constant (τ) and the time required for full charge (5τ).
Solution:
τ = R × C = 10,000 Ω × 100×10⁻⁶ F = 1 second
Time to steady state = 5τ = 5 seconds
After 1 second: 63.2% charged
After 5 seconds: 99.3% charged (practical completion)
Problem 2
An RL circuit has R = 50 Ω and L = 500 mH. Calculate τ and identify what percentage of current flows at t = τ and t = 3τ.
Solution:
τ = L / R = 0.5 H / 50 Ω = 0.01 seconds (10 ms)
At t = τ: Current = 63.2% of final value
At t = 3τ: Current = 95.0% of final value
The inductor initially opposes current flow, then gradually allows full current.
Problem 3
A capacitor must charge to 86.5% in 2 seconds. If R = 5 kΩ, what must C be (in microfarads)?
Solution:
86.5% charge occurs at t = 2τ
So: 2τ = 2 seconds, therefore τ = 1 second
τ = R × C
1 = 5,000 × C
C = 1/5,000 = 0.0002 F = 200 μF
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